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Which letters of the alphabet have lines of symmetry
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Namely, everywhere that the original formula has an " x ", I will now plug in an " x h "See the answer See the answer done loading (8f (x 3h) pf (x 2h) qf (x) rf (x h) 8f (x 2h))/60h^2 = f'' (x) O (h^3) Show transcribed image text Expert Answer Who are the experts?Clearly, h(x) = (mx b)(nx c) is a polynomial of degree 2 and h(x) has two roots The respective roots are when f(x) = 0 and g(x) = 0 This means the graph of h(x) crosses the xaxis at the same two points as f(x) and g(x) Thus, if there are points of tangency then they must occur at these common points on the xaxis
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G \ n U c \ Z V _ Y W Y Z V X _ Y Z X X Y Z W Z n U c j Y Z _ j Z Y W _ X ¹ h j Y Z W X Y _ j Y X W ¹ YFirst find h(7) h(x) = 3x14 h(7) = 3(7)14 h(7) = 2114 h(7) = 7 Then h1 (h(7)) = h1 (7) = then find h1 of 7 by plugging 7 in for x h1 (x) = (x14)/3 h1 (7) = (714)/3 h1 (7) = 21/3 h1 (7) = 7 h1 (h(7)) = h1 (7) = 7 So when a function is composed with its inverse, you get a function that gives you back the same number for y that youGiven that f (x) = 3x 2 2x, find f (x h) This one feels wrong, because it's asking me to plug something that involves x in for the original x But this evaluation works exactly like all the others;
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